Question on: SS2 Mathematics - Algebraic Fractions
Solve \(\frac{3x + 2}{5} = \frac{8}{x}\)
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\[\frac{3x + 2}{5} = \frac{8}{x}\]
\(x(3x + 2) = 40\)
\(3x^{2} + 2x = 40\)
\(3x^{2} + 2x - 40 = 0\)
\((3x - 10)(x + 4) = 0\)
\(3x - 10 = 0 or x + 4 = 0\)
\(x = \frac{10}{3} or x = - 4\)
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