Question on: WAEC Mathematics - 2005
Solve the equation (2^7 = 8^{5-x})
A
\(\frac{5}{8}\)
B
\(\frac{8}{3}\)
C
\(\frac{3}{2}\)
D
\(\frac{15}{4}\)
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Correct Option: B
(2^7 = 2^{3(5-x)}\Rightarrow 7 = 3^{5-x} \Rightarrow 7 15 - 3x<br /> \Rightarrow -8 = -3x \Rightarrow x = \frac{8}{3})
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