Question on: WAEC Mathematics - 2005
Solve the equation \(2^7 = 8^{5-x}\)
A
\(\frac{5}{8}\)
B
\(\frac{8}{3}\)
C
\(\frac{3}{2}\)
D
\(\frac{15}{4}\)
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Correct Option: B
\(2^7 = 2^{3(5-x)}\Rightarrow 7 = 3^{5-x} \Rightarrow 7 15 - 3x\
\Rightarrow -8 = -3x \Rightarrow x = \frac{8}{3}\)
\Rightarrow -8 = -3x \Rightarrow x = \frac{8}{3}\)
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