Question on: WAEC Mathematics - 1990
Solve the equation 2a\(^2\) - 3a - 27 = 0
A
3/2, 9
B
-2/3, 9
C
3, 9/2
D
-3, -9/2
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Correct Option: E
2a\(^2\) - 3a - 27 = 0
2a\(^2\) - 9a + 6a - 27 = 0
a(2a - 9) + 3(2a - 9) = 0
(a + 3)(2a - 9) = 0
a = -3 or a = \(\frac{9}{2}\)
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