Question on: WAEC Mathematics - 2000
Solve the equation 3 + 5x - 2x2 = 0
A
\(-\frac{1}{2},-3\)
B
2, 3
C
-2, 3
D
\(-\frac{1}{2},3\)
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Correct Option: D
\(3 + 5x - 2x^2 = 0\
3 + 6x - x - 2x^2 = 0\
3(1 + 2x) - x(1 + 2x) = 0\
(3-x)(1+2x)=0\
3-x = 0 \hspace{1mm}or \hspace{1mm}1+2x = 0\
x = 3\hspace{1mm} x = -\frac{1}{2}\
x = 3 \hspace{1mm}or\hspace{1mm} x =-\frac{1}{2}\)
3 + 6x - x - 2x^2 = 0\
3(1 + 2x) - x(1 + 2x) = 0\
(3-x)(1+2x)=0\
3-x = 0 \hspace{1mm}or \hspace{1mm}1+2x = 0\
x = 3\hspace{1mm} x = -\frac{1}{2}\
x = 3 \hspace{1mm}or\hspace{1mm} x =-\frac{1}{2}\)
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