Solve the equation 3y 2 27y - WAEC Mathematics 2000 Question
Solve the equation \(3y^2 = 27y\)
A
y = o or 3
B
y = 0 or 9
C
y = -3 or 3
D
y = 3 or 9
correct option: b
\(3y^2 = 27y\
3y^2 - 27y = 0\
3y(y - 9) = 0\
3y = 0 or y - 9 = 0\
y = 0 or y = 9\
y = 0 or 9\)
3y^2 - 27y = 0\
3y(y - 9) = 0\
3y = 0 or y - 9 = 0\
y = 0 or y = 9\
y = 0 or 9\)
Please share this, thanks:
Add your answer
No responses