Question on: WAEC Mathematics - 2000
Solve the equation \(3y^2 = 27y\)
A
y = o or 3
B
y = 0 or 9
C
y = -3 or 3
D
y = 3 or 9
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Correct Option: B
\(3y^2 = 27y\
3y^2 - 27y = 0\
3y(y - 9) = 0\
3y = 0 or y - 9 = 0\
y = 0 or y = 9\
y = 0 or 9\)
3y^2 - 27y = 0\
3y(y - 9) = 0\
3y = 0 or y - 9 = 0\
y = 0 or y = 9\
y = 0 or 9\)
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