Question on: WAEC Mathematics - 1993
Solve the equation x\(^2\) - 2x - 3 = 0
A
(-3, 1)
B
(-1, -3)
C
(3,1)
D
(43, 0)
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Correct Option: E
x\(^2\) - 2x - 3 = 0
x\(^2\) - 3x + x - 3 = 0
x(x - 3) + 1(x - 3) = 0
(x + 1)(x - 3) = 0
x = (-1, 3)
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