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Solve the equations m2 n2 29 m n 7 - JAMB Mathematics 2001 Question

Solve the equations
m2 + n2 = 29
m + n = 7
A
(2, 3) and ( 3, 5)
B
(2, 5) and (5, 2)
C
(5, 2) and ( 5, 3)
D
(5, 3) and (3, 5)
correct option: b

m2 + n2 = 29 .......(1)

m + n = 7 ............(2)

From (2),

m = 7 - n

but m2 + n2 = 29, substituting;

(7-n)2 + n2 = 29

49 - 14n + n2 + n2 = 29

=> 2n2 -14n + 20 = 0

Thus n2 -7n + 10 = 0

Factorizing;

(n-5)(n-2) = 0

n - 5 = 0, => n = 5

n - 2 = 0, => n = 2.

When n = 5,

m + n = 7, => m = 2,

When n = 2,

m + n = 7, => m = 5.

Thus (m,n) = (5,2) and (2,5)

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