Question on: JAMB Mathematics - 2023
Solve the following quadratic inequality: \(x^2 - x\) - 4 ≤ 2
\(-3 < x < 2\)
\(-2 ≤ x ≤ 3\)
\(x ≤ -2, x ≤ 3\)
\(-2 < x < 3\)
Let's solve the quadratic inequality:
\[ x^2 - x - 4 \leq 2 \]
First, bring all terms to one side to form a quadratic expression:
\[ x^2 - x - 6 \leq 0 \]
Now, factor the quadratic expression:
\[ (x - 3)(x + 2) \leq 0 \]
Now, identify the intervals where this expression is less than or equal to zero by considering the signs of the factors:
1. When \( x - 3 \leq 0 \) and \( x + 2 \geq 0 \):
- \( x \leq 3 \)
- \( x \geq -2 \)
2. When \( x - 3 \geq 0 \) and \( x + 2 \leq 0 \):
- \( x \geq 3 \)
- \( x \leq -2 \)
Combine the intervals:
\[ -2 \leq x \leq 3 \]
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