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Question on: JSS2 Mathematics - Linear Inequalities

Solving and Graphing βˆ’3π‘₯+6≀9

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Start with the inequality:

βˆ’3π‘₯+6≀9

Subtract 6 from both sides:

βˆ’3π‘₯≀3

Divide both sides by -3 and reverse the inequality:

π‘₯β‰₯βˆ’1

Β 

Graphical Representation:

  • Draw a number line.
  • Place a closed circle at π‘₯=βˆ’1(because -1 is included).
  • Shade the region to the right of -1.

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