Question on: WAEC Mathematics - 2014
Subtract (\frac{1}{2})(a - b - c) from the sum of (\frac{1}{2})(a - b + c) and (\frac{1}{2})
(a + b - c)
A
\(\frac{1}{2}\) (a + b + c)
B
\(\frac{1}{2}\) (a - b - c)
C
\(\frac{1}{2}\) (a - b + c)
D
\(\frac{1}{2}\) (a + b - c)
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Correct Option: A
(\frac{1}{2})(a - b + c) + (\frac{1}{2})(a + b - c) - [(\frac{1}{2}) (a - b - c)]
(\frac{1}{2}a - \frac{1}{2}b + \frac{1}{2}c + \frac{1}{2}a + \frac{1}{2}b - \frac{1}{2}c - \frac{1}{2}a + \frac{1}{2}b + \frac{1}{2}c)
= (\frac{1}{2}a + \frac{1}{2}b + \frac{1}{2}c)
= (\frac{1}{2}(a + b + c))
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