Question on: JAMB Mathematics - 1994
The angle of depression of a boat from the top of a cliff 10m high is 30. How far is the boat from the foot of the cliff?
A
\(\frac{5√3m}{3}\)
B
5√3m
C
10√3m
D
\(\frac{10√3m}{3}\)
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Correct Option: C
RQP = 90o
PQS = 30o but
RQS = 90o = \(\frac{RS}{10}\)
RS = 10 tan 60o
RS = 10 tan 60o
RS = 10√3m
PQS = 30o but
RQS = 90o = \(\frac{RS}{10}\)
RS = 10 tan 60o
RS = 10 tan 60o
RS = 10√3m
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