Question on: JAMB Mathematics - 1997
The angle of elevation of a building from a measuring instrument placed on the ground is 30o. If the building is 40m high, how far is the instrument from the foot of the building?
A
\(\frac{20}{β3}\)m
B
\(\frac{40}{β3}\)m
C
20β3m
D
40β3m
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Correct Option: D
\(\frac{40}{x}\) = tan 30o
x = \(\frac{40}{tan 36}\)
= \(\frac{40}{1\sqrt{3}}\)
= 40β3m
x = \(\frac{40}{tan 36}\)
= \(\frac{40}{1\sqrt{3}}\)
= 40β3m
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