The apparent weight of a body fully immersed in... - WAEC Physics 2001 Question
The apparent weight of a body fully immersed in water is 32N and its weight in air is 96N. Calculate the volume of the body. [Density of water = 1000kgm-3, g = 10ms-2]
A
8.9 x 10-3m3
B
6.4 x 10-3m3
C
3.2 x 10-3m3
D
3.0 x 10-3m3
correct option: b
Upthrust = 96 - 32 = 64N
mass(m) = \(\frac{64}{10} = 6.4 kg\)
volume = \(\frac{mass}{Density} = \frac{6.4}{1000}\)
= 6.4 x 10-3m3
mass(m) = \(\frac{64}{10} = 6.4 kg\)
volume = \(\frac{mass}{Density} = \frac{6.4}{1000}\)
= 6.4 x 10-3m3
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