Question on: WAEC Mathematics - 1990
The bearing of a point X from a point Y is 074°. What is the bearing of Y from X?
A
106o
B
146o
C
164o
D
254o
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Correct Option: D
< YXS = 74° (alternate angles, N\(_1\) S\(_1\) // N\(_2\) S\(_2\))
N\(_2\) E\(_2\) S\(_2\) = 180°
\(\therefore\) Bearing of Y from X = 180° + 74°
= 254°
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