Question on: WAEC Mathematics - 2003
The bearing of P from Q is x, where 270o < x < 360o. Find the bearing of Q from P
A
(x - 90)o
B
(x-270)o
C
(x - 135)o
D
(x - 180)o
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Correct Option: D
Bearing of Q and P
\(180^{\circ} – (360^{\circ}-x)\
180^{\circ}-360^{\circ}+x\
-180^{\circ}+x\
x-180^{\circ}\)
\(180^{\circ} – (360^{\circ}-x)\
180^{\circ}-360^{\circ}+x\
-180^{\circ}+x\
x-180^{\circ}\)
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