Question on: WAEC Physics - 1994
The density of a body is (5\times10^3kgm{^-3}) and it weighs 1N in air. Calculate the apparent weight of the body when totally immersed in water. (Density of water =(10^3kgm{-3}, g= 10ms^{-2}
A
0.02N
B
0.08N
C
0.20N
D
0.80N
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Correct Option: D
Upthrust = weight of the water displaced =pvg= 1000 x 2 x (10^{-5})=0.20N \ Apparent weight = weight in air – upthrust = 1-0.2N=0.8N
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