Question on: WAEC Mathematics - 2017

The diagonal of a square is 60 cm. Calculate its peremeter

A
20\(\sqrt{2}\)
B
40\(\sqrt{2}\)
C
90\(\sqrt{2}\)
D
120\(\sqrt{2}\)
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Correct Option: D

\(60^2 + x^2 + x^2\)

\(360^2 = 2x^2\)

\(x^2\) = 1800

x = \(\sqrt{1800}\)

x = 42.4264

x = 42.4264

perimeter = 4x

= 4 x 42.4264

= 169.7056

= 120\(\sqrt{2}\)

= 120\(\sqrt{2}\)

 

 

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