Question on: JAMB Mathematics - 1999
A
64 square units
B
128/3 square units
C
64/3 square units
D
32 square units
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Correct Option: C
\(\int_0 ^4 x^2 dx = \left[\frac{1}{3}x^2+C\right]_0 ^4\\
=\frac{1}{3}\times 4^3 - \frac{1}{3}\times 0^3\\
=\frac{64}{3}-0\\
=\frac{64}{3}\)sq units
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