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The diagram above shows the capacitors C1 C2 an... - JAMB Physics 2001 Question

The diagram above shows the capacitors C1, C2 and C3 2μF, 6μF and 3μF respectively. The potential difference across C1, C2 and C3 respectively are
A
4V, 6V and 2V
B
2V, 6V and 4V
C
6V, 4V and 2V
D
6V, 2V and 4V
correct option: d

C = Q/V => Q = CV : ∴V = Q/C

∴V1 = Q/C1; V2 = Q/C;

V3 = Q/C3

for series
1/C = 1/C1 + 1/C2 + 1/C3

= 1/2 + 1/6 + 1/3

= 3+1+2
_6

= 6/6 = 1

∴ C = 1μF = 1.0 x 10-6F

∴ Q = CV = 1.0 x 10-6 x 12

= 12.0 x 10-6C

∴V1 = Q/C1

= 12.0x10-6
2 x 10-6

= 6V

V2 = Q/C2

= 12.0x10-6
6 x 10-6

= 2V

V3 = Q/C3

= 12.0x10-6
3 x 10-6

∴ 6V, 2V and 4V

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