Question on: WAEC Physics - 1998
The diagram below illustrates an a.c.source of 50V(r.m.s.), \(\frac{100}{\pi}\)Hz connected in series with an inductor of inductor of inductance L and a resistor of resistance R. The current in the circuit is 2A and the p.d across L and R are 30V and 40V respectively. Calculate the power factor of the circuit
A
1.33
B
1.25
C
0.80
D
0.75
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Correct Option: E
cos\(\theta = \frac{R}{Z}\)
R = \(\frac{V}{I} = \frac{40}{2} = 20\)
Z = R2 + \(^X_L\) = 202 + 152 = 300
cos \(\theta = \frac{R}{Z} = \frac{20}{300} = 0.06\)
R = \(\frac{V}{I} = \frac{40}{2} = 20\)
Z = R2 + \(^X_L\) = 202 + 152 = 300
cos \(\theta = \frac{R}{Z} = \frac{20}{300} = 0.06\)
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