The diagram is a circle with centre O Find the ... - JAMB Mathematics 1992 Question
A
9(\(\pi - 2) cm^2\)
B
18\(\pi cm^2\)
C
9\(\pi cm^2\)
D
36\(\pi cm^2\)
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Correct Option: A
Area of the quadrant = (\frac{1}{4} \pi r^2 = \frac{1}{4} \pi (6)^2)
= (\frac{36 \pi}{4} = 9 \pi )
Area of the triangle = (\frac{1}{2} \times 6 = 18 \times \sin 90^o = 18)
Area of shaded portion =(9 (\pi ) - 18)cm^2) =
9((\pi - 2)cm^2).
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