The difference between an exterior angle of n -... - JAMB Mathematics 2023 Question
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6\(^o\), then the value of "n" is
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Let's denote the exterior angle of an \(n\)-sided regular polygon as \(E_n\). The exterior angle of an \(n\)-sided regular polygon is given by:
\[ E_n = \frac{360^\circ}{n} \]
Now, according to the given information:
\[ E_{n-1} - E_{n+2} = 6^\circ \]
Substitute the expressions for \(E_{n-1}\) and \(E_{n+2}\) into the equation:
\[ \frac{360^\circ}{n-1} - \frac{360^\circ}{n+2} = 6^\circ \]
To solve this equation, we can find a common denominator:
\[ \frac{360(n+2) - 360(n-1)}{(n-1)(n+2)} = 6 \]
Simplify the numerator:
\[ \frac{360n + 720 - 360n + 360}{(n-1)(n+2)} = 6 \]
Combine like terms:
\[ \frac{1080}{(n-1)(n+2)} = 6 \]
Now, cross-multiply and simplify:
\[ 1080 = 6(n-1)(n+2) \]
Divide both sides by 6:
\[ 180 = (n-1)(n+2) \]
Expand the right side:
\[ 180 = n^2 + 2n - n - 2 \]
Combine like terms:
\[ 180 = n^2 + n - 2 \]
Rewrite the equation in standard form:
\[ n^2 + n - 182 = 0 \]
Factor the quadratic expression:
\[ (n - 13)(n + 14) = 0 \]
This gives two possible solutions:
\[ n - 13 = 0 \quad \text{or} \quad n + 14 = 0 \]
\[ n = 13 \quad \text{or} \quad n = -14 \]
Since the number of sides (\(n\)) cannot be negative, we discard the solution \(n = -14\). Therefore, the correct value of \(n\) is:
\[ n = 13 \]
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