Question on: JAMB Physics - 2015
The dimension of universal gravitational constant is……….?
A
\( M^{–1}L^3 T^{–2} \)
B
ML3T2
C
ML3
D
MLT-2
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Correct Option: A
f α (MM ÷g2)
F(GMM ÷ r2) [G – gravitational constant]
GMM = Fr2
G = F02 ÷ MM = m × aπr2 ÷ MM (f = ma)
= (m × m5-2 × r2) ÷ MM
= (Kg.m52 × m2) ÷ Kg.Kg
=1 ÷ kg.m3.52
The dimension mathematically representation have a quantities of M, L AND T
M (Mass) = kg, L (Length) = M, T (Time) second
G = kg-1 m2.52(Using dimension rule)
M-1.L3.T-2
∴ The universal gravitational constant (G) =\( M^{–1}L^3 T^{–2} \)
F(GMM ÷ r2) [G – gravitational constant]
GMM = Fr2
G = F02 ÷ MM = m × aπr2 ÷ MM (f = ma)
= (m × m5-2 × r2) ÷ MM
= (Kg.m52 × m2) ÷ Kg.Kg
=1 ÷ kg.m3.52
The dimension mathematically representation have a quantities of M, L AND T
M (Mass) = kg, L (Length) = M, T (Time) second
G = kg-1 m2.52(Using dimension rule)
M-1.L3.T-2
∴ The universal gravitational constant (G) =\( M^{–1}L^3 T^{–2} \)
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