Home » Classroom » JAMB Physics 2014 Question

The distance between two successive crests of a... - JAMB Physics 2014 Question

The distance between two successive crests of a wave is 15cm and the velocity 300ms-1. Calculate the frequency.
A
2.0x102Hz
B
4.5x103Hz
C
2.0x103Hz
D
4.5x102Hz
correct option: c
Wavelength = 15cm = 0.15m

Velocity = 300m/s

V = fx

F = V/Wavelength

F = 300/0.15 Hertz

F = 2 x 103Hz
Please share this, thanks:

Add your answer

Notice: Posting irresponsibily can get your account banned!

No responses