The energy stored in a capacitor of capacitance... - WAEC Physics 1995 Question
The energy stored in a capacitor of capacitance 5μF is 40J. Calculate the voltage applied across its terminals?
A
4000V
B
200V
C
16V
D
6V
correct option: a
\(E = \frac{CV^{2}}{2}\)
\(V^{2} = \frac{2E}{C}\)
\(V^{2} = \frac{2\times 40}{5 \times 10^{-6}}\)
\(V^{2} = 16 \times 10^{6}\)
\(V = 4 \times 10^{3} = 4000v\)
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