The equation of the line in the graph is - JAMB Mathematics 1994 Question
A
3y = 4x + 12
B
3y = 3x + 12
C
3y = -4x + 12
D
3y = -4x + 9
correct option: c
Gradient of line = \(\frac{\text{Change in y}}{\text{Change in x}} = \frac{y_2 - y_1}{x_2 - x_1}\)
y2 = 0, y1 = 4
x2 = 3 and x1 = 0
\(\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}\)
Equation of straight line = y = mx + c
where m = gradient and c = y
intercept = 4
y = 4x + \(\frac{4}{3}\), multiple through by 3
3y = 4x + 12
y2 = 0, y1 = 4
x2 = 3 and x1 = 0
\(\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}\)
Equation of straight line = y = mx + c
where m = gradient and c = y
intercept = 4
y = 4x + \(\frac{4}{3}\), multiple through by 3
3y = 4x + 12
Please share this, thanks:
Add your answer
No responses