The equation of the line in the graph is - JAMB Mathematics 1994 Question

Gradient of line = (\frac{\text{Change in y}}{\text{Change in x}} = \frac{y_2 - y_1}{x_2 - x_1})

y₂ = 0, y₁ = 4

x₂ = 3 and x₁ = 0

(\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3})

Equation of straight line = y = mx + c

where m = gradient and c = y

intercept = 4

y = 4x + (\frac{4}{3}), multiple through by 3

3y = 4x + 12