The force of attraction between two point masse... - JAMB Physics 1998 Question
The force of attraction between two point masses is 10-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.
A
1.1 x 10-5N
B
3.3 x 10-5N
C
3.0 x 10-4N
D
9.0 x 10-4N
correct option: d
F (\alpha \frac{1}{r^2})
therefore, (\frac{F_1}{F_2}) = (\frac{r_1}{(r_2)^2})
(\frac{10^{-4}}{F_2}) = (\frac{(0.06)^2}{(0.18)^2})
F = 9 x 10-4N
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