Question on: JAMB Mathematics - 2004
A
68%
B
28%
C
17%
D
8%
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Correct Option: B
\(\begin{array}{c|c} \text{class-marks(x)} & \text{(freq. (f)} & \text{cum. freq.}\\hline 9 & &3.....3\14 & & 6....3 + 6 = 9\ 19 & & 9.....9 + 9 = 18\ 24 & & 3.....18 + 3 = 21\ 29 & & 2.....21 + 2 = 23\ 34 & & 2.....23 + 2 = 25\ & & 25\end{array}\)
% of students scoring more than 20 marks
= \(\frac{7}{25}\) x 100% = 28%
% of students scoring more than 20 marks
= \(\frac{7}{25}\) x 100% = 28%
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