Question on: SS2 Physics - Electromagnetic Waves
The intensity of an electromagnetic wave is 5 W/m2. What is the amplitude of the electric field in the wave?
1.0 V/m
Â
2.2 V/m
Â
3.5 V/m
Â
5.0 V/m
Explanation: The intensity of an electromagnetic wave is related to the square of the amplitude of the electric field. Using the formula intensity = (electric field amplitude)2 / (2 × impedance of free space), we can solve for the electric field amplitude. The impedance of free space is approximately 377 Ω. Substituting the given value and solving for the amplitude, we get (electric field amplitude)2 = (5 W/m2) × (2 × 377 Ω) = 3770 V2/m2. Taking the square root, we find the amplitude to be approximately 2.2 V/m.
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