The lowest note emitted by a stretched string h... - JAMB Physics 2021 Question
The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 180Hz?
A
4
B
3
C
2
D
1
correct option: b
f\(_{0}\) = 40H\(_{3}\)
1st overtone = 2f\(_{0}\) = 80H\(_{3}\)
2nd overtone = 3f\(_{0}\) = 120H\(_{3}\)
3rd overtone = 4f\(_{0}\) = 160H\(_{3}\)
4th overtone = 5f\(_{0}\) = 200H\(_{3}\)
Hence, the number of overtones between 40H\(_{3}\) and 180H\(_{3}\) = 3
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