The mass of silver deposited when a current of ... - JAMB Chemistry 2017 Question
The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is – (Ag = 108 F = 96500(mol-1)
A
54.0g
B
27.0g
C
13.5g
D
108.0g
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Correct Option: A
Recall that
m = (\frac{MmIt}{96500n})
Mm =108, t = 4830s
I = 10A, n = 1
m = 108 × 10 × ((\frac{4830}{96500})) × 1
m = 54.0g
Mass deposited = Mm × (\frac{It}{96500n})
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