Question on: JAMB Physics - 2017

For capacitance i n parallel, 2µF and 2µF are in parallel,

their equivalence is 2µF and 2µF = 4µF

The 4µF generated is now in series with the remaining 4µF.

The net capacitance for series connection is

(\frac{1}{C}) = (\frac{1}{4}) + (\frac{1}{4}) = 1 + (\frac{1}{4}) = (\frac{2}{4})

C = (\frac{4}{2})

= 2µF