The nth term of a sequence is given by 2 2n - 1... - JAMB Mathematics 2019 Question
The nth term of a sequence is given by 2\(^{2n - 1}\). Find the sum of the first four terms.
A
74
B
32
C
42
D
170
correct option: d
\(T_n = 2^{2n - 1}\)
\(T_1 = 2^{2(1) - 1} \)
= 2
\(T_2 = 2^{2(2) - 1}\)
= 8
\(T_3 = 2^{2(3) - 1}\)
= 32
\(T_4 = 2^{2(4) - 1}\)
= 128
\(T_1 + T_2 + T_3 + T_4 = 2 + 8 + 32 + 128\)
= 170
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