The nth term of a sequence is given by 3 2 n-2 ... - WAEC Mathematics 1992 Question
The nth term of a sequence is given by 3.2\(^{n-2}\). Write down the first three terms of the sequence.
A
2/3, 0, 6
B
3/2, 3, 6,
C
2/3, 3, 8/3
D
2/3, 3/4, 6
correct option: b
\(T_n = 3. 2^{n - 2} \
T_{1} = 3. 2^{1 - 2} = 3. 2^{-1} \
T_1 = \frac{3}{2} \)
\(T_2 = 3. 2^{2 - 2} \
T_2 = 3. 2^0 = 3\)
\(T_3 = 3. 2^{3 - 2} = 3. 2^1 \
T_3 = 6\)
The first 3 terms of the sequence are \(\frac{3}{2}\), 3 and 6.
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