Question on: JAMB Mathematics - 2013
The nth term of the progression (\frac{4}{2}), (\frac{7}{3}), (\frac{10}{4}), (\frac{13}{5}) is ...
A
\(\frac{1 - 3n}{n + 1}\)
B
\(\frac{3n + 1}{n + 1}\)
C
\(\frac{3n + 1}{n - 1}\)
D
\(\frac{3n - 1}{n + 1}\)
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Correct Option: B
Using Tn = (\frac{3n + 1}{n + 1}),
T1 = (\frac{3(1) + 1}{(1) + 1} = \frac{4}{2})
T2 = (\frac{3(2) + 1}{(2) + 1} = \frac{7}{3})
T3 = (\frac{3(3) + 1}{(3) + 1} = \frac{10}{4})
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