Question on: JAMB Mathematics - 2007
The nth term of the sequence (\frac{3}{2}), 3, 7, 16, 35, 74, ..., is
A
3.2n - 2
B
5.2n - 2 - n
C
\(\frac{3}{2}\)n
D
\(\frac{3}{2}\) n - 2
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Correct Option: B
T1 = (\frac{3}{2}) = (\frac{5}{2}) - 1
T2 = 3 = 5 - 3
T3 = 7 = 10 - 3 = 5.2 - 3
T4 = 16 = 20 - 4 = 5.22 - 4
T5 = 35 = 40 - 5 = 5.23 - 5
T6 = 74 = 80 - 6 = 5.24 - 6
Tn = 5.2n - 2 - n
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