Question on: WAEC Physics - 2016
The p.d across a parallel-plate capacitor is 103V. If the distance between the two plates is 10cm. Calculate the magnitude of the electric field strength between the plates.
A
1.0 x 104Vm-1
B
1.0 x 105Vm-1
C
1.5 x 105Vm-1
D
2.0 x 105Vm-1
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Correct Option: A
E = \(\frac{v}{d} = \frac{10^3}{0.1}\)
= 10000
= 1.0 x 104Vm-1
= 10000
= 1.0 x 104Vm-1
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