The perimeter of a sector of a circle of radius... - WAEC Mathematics 2011 Question

Perimeter of sector = 2r + (\frac{\theta}{360^o} \times 2\pi r)

(\pi + 8 = 2 \times 4 + \frac{\theta}{3360^o} \times 2 \pi \times 4)

(\pi + 8 + \frac{\theta}{360^o} \times 8 \pi)

P + 8 - 8 = (\frac{\theta \pi}{456o})

(\pi = \frac{\theta \pi}{45^o})

(\theta \pi = 45^o)