Question on: JAMB Mathematics - 2024
We are given a point \(B\) such that its distance from Y is always twice its distance from X. This means the ratio of the distances from B to X and from B to Y is 1:2.
Let d_X represent the distance from B to X, and d_Y represent the distance from B to Y. According to the given condition, we have:
\( d_Y = 2 \cdot d_X \)
This suggests that point B lies on a locus where the distance to Y is always twice the distance to X. This condition is satisfied by a specific geometric construction, which is the perpendicular bisector of the line segment XY. The perpendicular bisector divides the segment XY into two equal parts and places any point on it equidistant from X and Y, satisfying the given ratio of distances.
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