Question on: JAMB Chemistry - 2024
The pH of a 0.001 mol dm-3 of H2SO4 is
[Log102 = 0.3]
A
2.7
B
3.0
C
3.3
D
2.0
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Correct Option: A
H2SO4 is a strong acid and dissociates completely in water. Each molecule yields two H+ ions.
- Calculate the concentration of H+ ions: 0.001 mol/dm³ * 2 = 0.002 mol/dm³.
- Calculate pH: pH = -log10[H+] = -log10(2 x 10-3) = -(log102 + log1010-3) = -(0.3 - 3) = 2.7
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