Question on: JAMB Chemistry - 1998
The pH of a solution obtained by mixing 100cm3 of a 0.2M solution of NaOH is?
A
1.3
B
7.0
C
9.7
D
12.7
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Correct Option: D
1. **Calculate the moles of NaOH:**
* Moles = Molarity × Volume (in Liters)
* Volume = 100 cm³ = 0.1 L
* Moles of NaOH = 0.2 M × 0.1 L = 0.02 moles
2. **NaOH is a strong base and completely dissociates in water.** Therefore, the concentration of hydroxide ions (OH⁻) is equal to the concentration of NaOH.
* [OH⁻] = 0.02 moles / 0.1 L = 0.2 M
3. **Calculate the pOH:**
* pOH = -log₁₀[OH⁻]
* pOH = -log₁₀
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swiftshoretosns12
April 15 2025
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