The probabilities that a man and his wife live ... - JAMB Mathematics 2012 Question
The probabilities that a man and his wife live for 80 years are
A
B
C
D
correct option: d
Man lives = (\frac{2}{3}) not live = (\frac{1}{3})
Wife lives = (\frac{3}{5}) not live = (\frac{2}{5})
(P(\frac{2}{3} \times \frac{2}{5}) + (\frac{2}{5} \times \frac{1}{3}) + (\frac{2}{3} \times \frac{3}{5}))
= (\frac{4}{15} + \frac{3}{15} + \frac{6}{15})
= (\frac{13}{15})
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