Question on: WAEC Mathematics - 2005
The probability that John and James pass an examination are 3/4 and 3/5 respectively, find the probability of both boys failing the examination
A
\(\frac{1}{10}\)
B
\(\frac{3}{10}\)
C
\(\frac{9}{20}\)
D
\(\frac{11}{20}\)
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Correct Option: A
Prob.(John pass)\(=frac{3}{4}\) prob.(John fail) \(=1-frac{3}{4}=\frac{1}{4}\)
Prob.(James pass) \(=frac{3}{5}\) Prob.(James fail) \(=1-frac{3}{5}=\frac{2}{5}\)
Prob(both boys fail)\(=frac{1}{4}\times \frac{2}{5}=\frac{1}{10}\)
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