Question on: WAEC Physics - 2011
The radius of a wheel is 30.0 cm and that of its axle is 6.0cm. Calculate the effort required to lift a load of 120.0N using this machine. Assuming 100% efficiency
A
600.0N
B
40.0N
C
24.0N
D
20.0N
Ask EduPadi AI for a detailed answer
Correct Option: C
V.R = \(\frac{R}{r} = \frac{30}{6} = 5\)
\(\gamma = \frac{M.A}{V.R} \times \frac{100}{1} \)
M.A = \(\frac{100 \times 5}{100} = 5\)
Effort = \(\frac{L}{M.A} = \frac{120}{5}\)
= 24N
\(\gamma = \frac{M.A}{V.R} \times \frac{100}{1} \)
M.A = \(\frac{100 \times 5}{100} = 5\)
Effort = \(\frac{L}{M.A} = \frac{120}{5}\)
= 24N
Add your answer
Please share this, thanks!
No responses