The rate constant k for a second-order reaction... - SS2 Chemistry Chemical Kinetics Question

For a second-order reaction, the rate equation is given by:

rate = k[A]²

We can rearrange the equation to solve for the concentration:

rate = k[A]²

[A]² = rate / k

[A] = sqrt(rate / k)

Given that the rate constant (k) is 0.005 M^-1s^-1 and the initial concentration ([A]₀) is 0.20 M, we can substitute these values into the equation:

[A] = sqrt(rate / k) = sqrt([A]₀² - 2kt)

[A] = sqrt((0.20 M)² - 2 x 0.005 M^-1s^-1 x 60 s)

[A] ≈ 0.173 M

Therefore, the concentration of the reactant after 60 seconds is approximately 0.173 M.