Question on: WAEC Physics - 2013
The refractive index of a material is 1.5. Calculate the critical angle at the glass-air interface
A
19o
B
21o
C
39o
D
42o
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Correct Option: D
SinC = \(\frac{1}{n} = \frac{1}{1.5} = 0.6667\)
C = sin-10.6667
= 42o
C = sin-10.6667
= 42o
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