The remainder when 6p3 - p2 - 47p 30 is divided... - JAMB Mathematics 2013 Question

Let f(p) = 6p³ - p² - 47p + 30

Then by the remainder theorem,

(p - 3): f(3) = remainder R,

i.e. f(3) = 6(3)³ - (3)² - 47(3) + 30 = R

162 - 9 - 141 + 30 = R

192 - 150 = R

R = 42