Question on: JAMB Physics - 1990
The resistances of platinum wire at the ice and steam points are 0.75 ohm and 1.05 ohm respectively. Determine the temperature at which the resistance of the wire is 0.90 ohm
A
43.0oC
B
50.0oC
C
69.9oC
D
87.0oC
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Correct Option: B
100oC .... 1.05\(\theta\)
\(\theta\)oC .... 0.9\(\theta\)
0oC .... 0.75\(\theta\)
\(\frac{\theta - 0}{100 - 0}\) = \(\frac{0.9 - 0.75}{1.05 - 0.75}\)
\(\theta\) = 50oC
\(\theta\)oC .... 0.9\(\theta\)
0oC .... 0.75\(\theta\)
\(\frac{\theta - 0}{100 - 0}\) = \(\frac{0.9 - 0.75}{1.05 - 0.75}\)
\(\theta\) = 50oC
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