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The sum of the interior angle of a regular poly... - JAMB Mathematics 2005 Question

The sum of the interior angle of a regular polygon is 1800o. Calculate the size of one exterior angle of the polygon
A
30o
B
24o
C
18o
D
12o
correct option: a

Sum of interior ∠s = 1800o

∴(n - 2) 180o = 1800o

180n -360o = 1800o

180n = 1800o + 360o

180n = 2160o

n = 2160o/180o

n = 12 sides

Each exterior ∠ = 360o/n

= 360o/12

= 30o

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