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Question on: JAMB Mathematics - 2005

The sum of the interior angle of a regular polygon is 1800^o. Calculate the size of one exterior angle of the polygon

A

30^o

B

24^o

C

18^o

D

12^o

Ask EduPadi AI for a detailed answer

Correct Option: A

Sum of interior ∠s = 1800^o
∴(n - 2) 180^o = 1800^o
180n -360^o = 1800^o
180n = 1800^o + 360^o
180n = 2160^o
n = 2160^o/180^o
n = 12 sides
Each exterior ∠ = 360^o/n
= 360^o/12
= 30^o

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