The sum of the interior angles of regular polyg... - WAEC Mathematics 2012 Question
The sum of the interior angles of regular polygon is 1800o. How many sides has the polygon?
A
16
B
12
C
10
D
8
correct option: b
Sum = (n - 2)180
1800 = (n - 2)180
divide both sides by 180o
\(\frac{1800}{180}\) = (n - 2)\(\frac{180}{180}\)
10 = n - 2
10 + 2 = n
n = 12
1800 = (n - 2)180
divide both sides by 180o
\(\frac{1800}{180}\) = (n - 2)\(\frac{180}{180}\)
10 = n - 2
10 + 2 = n
n = 12
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